Skip to content
  • Start free trial
An original census record

Start a free trial to view

Get access to the original record, as well as a map showing the local area at the time

Household of Mary Earnshaw (born 1828, Yorkshire)

1881 England, Wales & Scotland Census in Wortley, Yorkshire,Yorkshire (West Riding), England

Mary Earnshaw and 6 other people are on this record


Get access to the original record, as well as a map showing the local area at the time

Mary Earnshaw's household

Female

Mary

Earnshaw

Head
Male

Sam

Earnshaw

Son
Female

Eliza

Earnshaw

Daughter
Male

Fred

Earnshaw

Son
Female

Sarah

Earnshaw

Grand Daughter
Female

Maude

Earnshaw

Grand Daughter
Male

Haydn

Earnshaw

Grand Son
First name(s) Mary
Last name Earnshaw
Relationship Head
Marital status Widow
Age 53
Birth year 1828
Birth place Penistone, Yorkshire, England

Household members (7 people)

First name(s)

Last name

Relationship

Marital status

Age

Birth year

Birth place

Full record

Mary

Earnshaw

Head

Widow

53

1828

Penistone, Yorkshire, England

Sam

Earnshaw

Son

Widower

28

1853

Silkstone, Yorkshire, England

Eliza

Earnshaw

Daughter

Single

15

1866

Bradfield, Yorkshire, England

Fred

Earnshaw

Son

Single

12

1869

Bradfield, Yorkshire, England

Sarah

Earnshaw

Grand Daughter

Single

7

1874

Bradfield, Yorkshire, England

Maude

Earnshaw

Grand Daughter

Single

5

1876

Bradfield, Yorkshire, England

Haydn

Earnshaw

Grand Son

Single

3

1878

Bradfield, Yorkshire, England

Explore Findmypast's newspaper collections

Explore the 1881 Census and millions of historical records for free with Findmypast. Find out more about the household of Mary Earnshaw in Wortley in 1881, and follow the Earnshaw family through time in other national records, newspapers and more.

We've found family trees for Mary Earnshaw

We’ve found Mary Earnshaw in 24 family trees. Find out more about Mary Earnshaw's household and view the Earnshaw family in family trees created by Findmypast members.

Not who you're looking for?